Now, let's find the pattern of integers that j follows
Substitute the i solution back into the original equation
j is always 67 more than 76 times an integer
So in what year will Halley's Comet be in the sky at the same as the cicadas?
Let's use k2 = 0. If we use negative numbers we get answers in the past. If we use larger k2's we go further into the future.
Thus in 15 more orbits, Halleys Comet will be in the sky with the cicadas who will have made 76 appearances since 1987.
Halley's Comet appears in years
Halley's Comet will appear in the year 3126 when the cicadas will also appear.
Doublechecking by using the cicadas equation
Yes, the cicadas will also appear in the year 3126 with Halley's Comet.
In the year 3126, will man still be alive to see Halley's Comet and the cicadas in the sky at the same time?
